Why relativistic momentum equals the following?

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The discussion centers on the derivation of relativistic momentum, specifically how to express momentum in terms of energy and mass. It highlights the equation P = √(γ² - 1) * mc, derived from the relationship between momentum and the Lorentz factor γ. Participants note that while using p = γmv is valid, eliminating velocity from the equations can lead to the same result. However, it is suggested that using the energy-momentum relation E² - p²c² = m²c⁴ is a more straightforward method to solve for momentum. The conversation emphasizes the importance of understanding these fundamental equations in relativistic physics.
Foruer
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In a solution to a problem we were given, it is written that a positron momentum with energy of 2mc2
(where γ=2) is √(γ2-1)*mc = √(4-1)*mc = √3*mc

How did they get that P=√(γ2-1)*mc?
 
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You are familiar with p = ϒmv right?
And also with ϒ = 1/√(1-(v/c)2) right?

Eliminate v from the two equations and what do you get?
 
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What I get is the answer ?:) thank you :wink:
 
While it gives you the right answer, it is much simpler to use the energy-momentum relation ##E^2 - p^2 c^2 = m^2 c^4## and just solve for ##p##.
 
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