Why time in formula accelarion has exponent two

[edephysic]

hello folks,

I am learning about how create a equation dimensional to formula Force (m*a).
I know this formula written this way:
[F]=[ma]
where:
m=mass
a=acceleration -> L/T²

The result is [F] = M * (L/T²) * L⁰
My result it's right?

Why T, relative time, has exponent two in formula acceleration?

Sorry about my English, I am learning this language :)
thanks

 

[Doc Al]

Why T, relative time, has exponent two in formula acceleration?

Recall that acceleration is a velocity ([L]/[T]) divided by time [T]. ([L]/[T])/[T] = [L]/[T²]

 

[edephysic]

I think I understood.
It's the same: [L][T^-2]?

The formula referent equation dimensional it's right?
thanks

[UPDATE]
Therefore:
the formula relative equation dimensional is: [F] = [M][L][T^-2]?
I understood, the exponent two it is achieved through rule potentiation.

 

[phinds]

to expand a bit on what Doc Al said, look at it this way:

Velocity is rate per unit of time, or for example, distance per second.

Acceleration is THAT per second and since "THAT" is "distance per second" you have "(distance per second) per second" and we write that as (D/T)/T, or D/T²

 

[Doc Al]

I think I understood.
It's the same: [L][T^-2]?

Yes. 1/[T^2] = [T^(-2)]

Therefore:
the formula relative equation dimensional is: [F] = [M][L][T^-2]?

Good.