Why we do not consider the divergence due to mass-shell in QED?

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Please teach me this:
Why we do not consider the divergences in loops in QED when p^{2}→m^{2} but only consider the soft photon when k^{2}→0(IR divergence) and UV divergence?
Thank you very much in advance.
 
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p²-m² is always regulated via the "iε-Term" and is evaluated via the Cauchy contour integral
 
Why we have not the same consideration when m=0?
 
Sorry,Now I have understood.Applying Cauchy's theorem when m=0(so k^{2}→0)
we have divergence(IR divergence)
 
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