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Wien Bridge Frequency Proof

  1. Apr 1, 2008 #1
    [SOLVED] Wien Bridge Frequency Proof

    1. The problem statement, all variables and given/known data

    The ac bridge circuit shown is called a Wien bridge (also Wein bridge).
    Wien Bridge.png

    Show that when the bridge is balanced, frequency is found by the Eqn attached. Eqn.png


    2. Relevant equations

    w=2*pi*f

    Using the number from each branch as a guide, the general solution to AC bridges is Z4 = (Z3/Z1)*Z2

    3. The attempt at a solution

    I keep trying to solve for impedences to plug into the second equation provided, but my j values do not cancel and the equation left is rather messy (R2R4C2C4*w^2 +jw(RzR4C2 -R2C2 -R4C4) +1 = 0.

    For my impedence values I have been using
    Z1 = R1
    Z2 = R2 -j/wC2
    Z3 = R3
    Z4 = (R4/jwC4)/(R4 +jwC4)

    Any help with this would be greatly appreciated.
     
  2. jcsd
  3. Apr 1, 2008 #2
    I think [tex] Z_4 = \frac {-jR_4} {\omega C_4 (R_4 - \frac{j}{\omega C_4})} [/tex]


    Both the real and the imaginary parts of Z4 = (Z3/Z1)*Z2 must be 0
     
  4. Apr 2, 2008 #3
    Actually, I think our Z4 values are the same, since -j = 1/j. But thank you! I managed to figure it out after you got me thinking about real and imaginary parts.

    It's fairly simple, actually: I just had to equate the real parts from my equation so that R2R4C2C4*w^2 + 1 = 0 (and then I took absolute value).
     
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