Will Mixing Ideal Gases at the Same Temperature Cause a Temperature Change?

AI Thread Summary
When two ideal gases mix without a chemical reaction, there is no temperature change if they are initially at the same temperature. If they start at different temperatures, the final temperature will be an average between the two. The assumption is that the mixture's volume equals the sum of the original volumes, with no external heat exchange or work done. Any chemical reaction complicates the calculation of the final temperature. Thus, the absence of a reaction is key to maintaining the initial temperature when mixed at the same temperature.
Outrageous
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When 2 ideal gas mix, there will be no temperature change. Is that because there will not be any chemical reaction occur, so no temperature change?
thank
 
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Outrageous said:
When 2 ideal gas mix, there will be no temperature change. Is that because there will not be any chemical reaction occur, so no temperature change?
thank

If they are at different temperatures when you mix them, and there is no chemical reaction, the temperature of the mixture will be different than the two temperatures they had before you mixed them. That temperature will be somewhere in between the two.

That means, if they are at the same temperature when you mix them, and there is no chemical reaction, the final temperature will be the same as the initial temperatures.

There may or may not be a chemical reaction. If there is a chemical reaction, then figuring the final temperature is more complicated.

This all assumes that the volume of the mixture is the sum of the original volumes and that no heating or cooling is done from the outside and they don't do any work on each other or the outside and no particles are gained from or lost to the outside.
 
Rap said:
That means, if they are at the same temperature when you mix them, and there is no chemical reaction, the final temperature will be the same as the initial temperatures..

Exactly what I want to ask . Thank you
 
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