Will the Block Move and What is Its Acceleration?

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A block weighing 35.0 N is subjected to a horizontal force of 41 N on a table, with static and kinetic friction coefficients of 0.650 and 0.420, respectively. To determine if the block will move, the static friction force must be calculated, which is 22.75 N (35.0 N * 0.650). Since the applied force of 41 N exceeds the static friction force, the block will move. Once in motion, the kinetic friction force is 14.70 N (35.0 N * 0.420), resulting in a net force of 26.30 N (41 N - 14.70 N) acting on the block. The acceleration can then be calculated using Newton's second law, yielding an acceleration of approximately 0.75 m/s².
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A block whose weight is 35.0 N rests on a horizontal table. A horizontal force of 41 N is applied to the block. The coefficients of static and kinetic friction are 0.650 and 0.420 N, respectively. Will the block move under the influence of the force, and, if so, what will be the block's acceleration?

m/s^2= ?
 
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vntraderus said:
A block whose weight is 35.0 N rests on a horizontal table. A horizontal force of 41 N is applied to the block. The coefficients of static and kinetic friction are 0.650 and 0.420 N, respectively. Will the block move under the influence of the force, and, if so, what will be the block's acceleration?

m/s^2= ?

Do you want someone here to replace the question mark with an answer, or do you want to know what m/s2 means?

I should point out that PF rules state that we must see some work from you, and we will not give out final solutions to homework problems.

So, what work have you done so far?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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