Wondering where the distance formula from acceleration due to gravity comes from

AI Thread Summary
The distance formula d=1/2gt^2 derives from integrating the acceleration due to gravity, represented as a constant g. To obtain this formula, one must integrate the acceleration function twice with respect to time, which introduces two arbitrary constants of integration. Solving the initial value problem with conditions y(0)=0 and y'(0)=0 leads to the specific solution for distance fallen under gravity. This process highlights the relationship between acceleration, velocity, and displacement in the context of free fall. Understanding this derivation is essential for grasping the fundamentals of motion under constant acceleration.
Icedfire01
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Pretty much like the title says. I'm having a hard time finding where the formula: d=1/2gt^2 comes from. Any help would be greatly appreciated.
 
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If a=g, then integrate twice with respect to time !
 
That's almost right. When you integrate twice you pick up two arbitrary constants of integration. To really derive the formula you would have to solve the following initial value problem:

\frac{d^2y}{dt^2}=-g

y(0)=0

y'(0)=0.
 
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