Work against the external pressure

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The discussion revolves around calculating work against external pressure during the reaction of nitrogen and hydrogen to form ammonia. The user is attempting to apply the formula W = -PexΔV but is unsure how to determine ΔV, as initial and final volumes are not provided. They consider using the ideal gas law, PV = nRT, to find volume but seek clarification on whether work (W) is indeed the desired outcome. The reaction is noted to be exothermic, which may influence the calculations. Further guidance is requested to proceed with the calculations effectively.
omni
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in the picture you can see the reaction.

it's known that 2 mol nitrogen reaction with 6 mol hydrogen gas to create ammonia.
what is the work against the external pressure in 1 Atm in 25 degrees Celsius?

i think i need to use this formula:W=-PexdeltaV.
but i can't know what is deltaV.

i just know that -Pex=-1atm. 1atm=101,325 Pa
and is a exothermic reaction.

how can i keep on from here?

thanks.
 

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ΔV is just a volume change - what is an initial volume? What is a final volume?
 
Is not given in the description question.
maybe i can use PV=nRT?
and from this formula i can find V?

what are you think?
and just to be sure W is what i need to find yes?

thanks.
 

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