Work and Energy Question? Help

AI Thread Summary
A user is confused about a work and energy problem involving a 50-kg crate being pulled with a force of 100N at a 37-degree angle, facing a frictional force of 50N. They calculated the work done by the pulling force as 3200J and the work done by friction as -2000J, resulting in a net work of 1200J. The user questions where this net work goes and whether it is stored in the object. Responses clarify that the net work corresponds to the total kinetic energy added to the crate, which can be used to calculate its velocity after moving 40m. The discussion emphasizes understanding the work-energy theorem and the importance of calculating kinetic energy.
chesshaha
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Work and Energy Question?? PLZ Help!



Hi, I am having a stupid question with a classic work and engergy problem.

Suppose you have A 50-kg crate is pulled 40m along a horizontal floor by a constant force exerted by a person, F done of by the pulling force is 100N, which at 37 degrees. F done by the friction is 50N.

I calculated the work done by the pulling force, which is 3200J.
I also calculated the work done by the frictional force, which is -2000J.

My question is what happened to the net work, 1200J.
Does the energy stores inside the crate, what?

PLZ HELP! :cry: :confused: :-p :wink:
 
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Please post in the homework section.
 
I need to see some work if I am to help you.

Do use the homework help section next time.
 
Last edited:
The net work done on an object is the total kinetic energy of the object...this is the work-KE theorem. So, in moving your 50 kg mass 40m with a net work of 1200J, you add 1200J of KE to the object. From this you can calculate the velocity of the object at the time you reach 40m.
 
I don't have a homework problem, and this is not a homework question, read my post please.

Im asking where did the net work, 1200J went? Did it store in the object?
 
leright said:
The net work done on an object is the total kinetic energy of the object...this is the work-KE theorem. So, in moving your 50 kg mass 40m with a net work of 1200J, you add 1200J of KE to the object. From this you can calculate the velocity of the object at the time you reach 40m.

You basicly just re-stated my question, thanks...
 
I don't think that's a restatement of your problem at all. You don't mention velocity for one thing.

What exactly is the problem you are tring to solve? What do you have to calculate?

Read again and try what leright suggests.
 
chesshaha said:
You basicly just re-stated my question, thanks...

Lose the attitude.
 
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