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Work done along incline plane

  1. Oct 23, 2007 #1
    1. The problem statement, all variables and given/known data
    There is a plane inclined 30degree. A box with 4.0kg mass is pushed up the plane with 128J. The kinetic friction between the plane and the box is 0.30. What is the distance will the box travelled until it stops?


    2. Relevant equations



    3. The attempt at a solution
    Fn=MG Cos theta
    = 4.0 x 9.8 x cos30
    = 33.98N

    Friction force = 33.98N x 0.30
    = 10.194N

    F = mg sin theta
    = 4 x 9.8 x sin30
    = 19.6N

    19.6N - 10.194N = 9.406N

    E = Fd

    128J = 9.406N x d
    d = 13.61M


    i need help urgently :(
     
  2. jcsd
  3. Oct 23, 2007 #2
    anyone? pls.........
     
  4. Oct 24, 2007 #3

    rl.bhat

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    Homework Helper

    Mass is pushed up the plane. Therefore the frictional force acts in the direction of mg sin theta. Hence net retarding force is = 19.6N + 10.194N
     
  5. Oct 24, 2007 #4
    yeah, i got that , the displacement is 4.29meter

    thx a lot
     
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