- #1
whynot314
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The facing surfaces of two large parallel conducting plates separated
by 10.0 cm have uniform surface charge densities that are equal in magnitude but
opposite in sign. The difference in potential between the plates is 500 V. An electron is released from rest next to the negatively charged surface. Find the work done by the electric field on the electron as the electron moves from the release point to the positive plate.
Ok so I am getting -8E-17 J
by ΔU=qΔV, W=qΔV
and I know ΔV is positive because we are going form low potential to high potential therefore Δv=500V
so i am getting W=(-1.6E-19)(500)=-8E-17 however I am concerned because I am seeing a positive work somewhere else. and that just does not make sense to me. or can someone explain to me why this would be positive work?
by 10.0 cm have uniform surface charge densities that are equal in magnitude but
opposite in sign. The difference in potential between the plates is 500 V. An electron is released from rest next to the negatively charged surface. Find the work done by the electric field on the electron as the electron moves from the release point to the positive plate.
Ok so I am getting -8E-17 J
by ΔU=qΔV, W=qΔV
and I know ΔV is positive because we are going form low potential to high potential therefore Δv=500V
so i am getting W=(-1.6E-19)(500)=-8E-17 however I am concerned because I am seeing a positive work somewhere else. and that just does not make sense to me. or can someone explain to me why this would be positive work?