Work done by variable force

In summary: N/(400N/m) = 0.025mIn summary, the problem involves finding the resulting spring compression when a 10-N force is used to compress a spring with a spring constant of 4.0x10^2N/m. The spring constant indicates that for each meter the spring is compressed, it will push back with 400 Newtons of force. To solve for the compression, we must use Newton's first law to set the forces in opposite directions equal to 0, and then solve for the compression (x) where the spring exerts 10 Newtons of force. The resulting spring compression is 0.025 meters.
  • #1
kallied
2
0

Homework Statement


if a 10-N force is used to compress a spring with a spring constant of 4.0x10^2N/m, what is the resulting spring compression?


Homework Equations





The Attempt at a Solution

 
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  • #2
The spring constant tells you something about how great a force is needed to compress the spring 1 m so see if the units give you a hint. It is just a ratio.
I think the problem is about finding the dx (The displacement). Alternativly use Newtons 1. law to see where it stands still, and the force seems constant to me:
Fhook - Fpress = 0 => kx - Fpress = 0 <=> x = Fpress/k
Do you get the idea?
 
  • #3
no not really :(
 
  • #4
What the spring constant says is: for each meter the spring is compressed, the spring will push back with 400 Newtons more force. The spring in your problem will push back with 400x Newtons of force, where x is the distance you compress it in meters. To get your answer, you must find the compression (x) where this spring exerts 10 Newtons of force.
 
  • #5
Try imangining you compressing a spring. If you pressed with 10 N, then the spring would try to oppose it(You can feel it trying). If you pressed it until it was half as wide as initially, and stood still there, then the acceleration of the spring equals zero(a=0). Then Newtons first law of motion states:
[itex] \sum F = 0[/itex]
The two forces are in opposite directions(you pressing and the spring pressing against)
[itex] Fhook-Fpress = 0 \,\Leftrightarrow \\ kx -10N = 0\\
kx = 10N [/itex]
 

What is work done by variable force?

Work done by variable force refers to the amount of energy transferred to an object by a force that changes in magnitude and/or direction as the object moves. It is a measure of the amount of force exerted over a given distance.

How is work done by variable force calculated?

To calculate work done by variable force, the formula W = ∫ F(x)dx is used, where W is work, F(x) is the variable force, and dx is the displacement of the object. This formula is derived from the concept of integration in calculus.

What is the unit of measurement for work done by variable force?

The unit of measurement for work done by variable force is the joule (J). One joule is equal to one newton-meter (N·m) of work.

What is the difference between work done by constant force and variable force?

The main difference between work done by constant force and variable force is that constant force maintains the same magnitude and direction throughout the displacement, while variable force changes in magnitude and/or direction as the object moves. This results in a different amount of work being done in each case.

What are some real-life examples of work done by variable force?

Some real-life examples of work done by variable force include pushing a shopping cart, rowing a boat, and riding a roller coaster. In each of these cases, the force applied to the object changes in magnitude and/or direction as it moves, resulting in varying amounts of work being done.

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