Work Done on Cart on Incline+Rest

AI Thread Summary
A 10-kg cart starts up an incline at 2 m/s and comes to rest after traveling 2.5 m. The total work done on the cart is being questioned, with options including -20J, -12J, 12J, 20J, or "Impossible to calculate." The work-energy theorem is recommended as the simplest approach to solve the problem, while an alternative method involves calculating the net force and acceleration along the incline. The discussion emphasizes the importance of understanding the work-energy theorem for efficient problem-solving.
Spartan Erik
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Homework Statement



A 10-kg cart starts up an incline with a speed of 2 m/s and comes to rest 2.5 m up the incline. The total work done on the cart is:

-20J, -12J, 12J, 20J, Impossible to calculate

Homework Equations



W = Fd
W = Fdcos(theta)

The Attempt at a Solution



I'm not sure how to approach this problem. W = Fdcos(theta) but there isn't a degree of incline given
 
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Spartan Erik said:

Homework Statement



A 10-kg cart starts up an incline with a speed of 2 m/s and comes to rest 2.5 m up the incline. The total work done on the cart is:

-20J, -12J, 12J, 20J, Impossible to calculate

Homework Equations



W = Fd
W = Fdcos(theta)

The Attempt at a Solution



I'm not sure how to approach this problem. W = Fdcos(theta) but there isn't a degree of incline given
If you are familiar with and understand the work-energy theorem, you should use that approach first, since it will be much simpler than an alternate approach. If you are not familar with that theorem, you can determine the net force acting parallel to the incline by first determining the acceleration parallel to the incline, then calculate the work done by that net force.
 
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