The discussion focuses on calculating the total work done on a 10-kg cart that starts with a speed of 2 m/s and comes to rest after moving 2.5 m up an incline. The total work done is determined using the work-energy theorem, which simplifies the calculation compared to using the force and distance approach. The net force acting parallel to the incline must be calculated to find the work done. The final answer is -20J, indicating that work is done against the motion of the cart.
PREREQUISITESThis discussion is beneficial for physics students, educators, and anyone studying mechanics, particularly those focusing on work and energy in inclined motion scenarios.
If you are familiar with and understand the work-energy theorem, you should use that approach first, since it will be much simpler than an alternate approach. If you are not familar with that theorem, you can determine the net force acting parallel to the incline by first determining the acceleration parallel to the incline, then calculate the work done by that net force.Spartan Erik said:Homework Statement
A 10-kg cart starts up an incline with a speed of 2 m/s and comes to rest 2.5 m up the incline. The total work done on the cart is:
-20J, -12J, 12J, 20J, Impossible to calculate
Homework Equations
W = Fd
W = Fdcos(theta)
The Attempt at a Solution
I'm not sure how to approach this problem. W = Fdcos(theta) but there isn't a degree of incline given