Work Power Engergy Thrown Toilet Roll Problem

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A pure silver Lions fan throws a 0.4 kg roll of toilet paper at 11.0 m/s from a height of 17.0 m. The discussion centers on using the conservation of energy principle, where initial kinetic energy (KE) and potential energy (PE) equal final KE. The equation used is mgh + 1/2mv^2 = 1/2mV^2, but confusion arises regarding the next steps after calculating initial energies. The direction of the throw is not specified, complicating the determination of the final velocity's direction. Understanding these energy concepts is crucial for solving the problem accurately.
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Homework Statement


A pure silver Lions fan throws a roll of toilet paper at 11.0 m/s from her seat at Ford's Field during a recent game. How fast is the 0.4 kg roll going when it strikes an opposition player 17.0 m below?

Homework Equations


1/2mv^2 = mgh <-- i think.

The Attempt at a Solution


I did 1/2mv^2 = mgh and got something like 18.25 and then got totally confused and did not know how to do it. Please help. I am totally lost. thanks please answer in the next 20 mintues and you will receive lots of love. Thanks.
 
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Yes, definitely an energy question! But I think you have oversimplified a bit. Wouldn't it be
Initial KE + initial PE = final KE
 
I did:
mgh+1/2mv^2
and got an answer and I don't know what to do from there.
 
Initial KE + initial PE = final KE
mgh+1/2mv^2 = 1/2mV^2
Fill in the numbers.
 
Which direction are they throwing the roll in?
 
We can find the magnitude of the velocity from the final KE. But not the direction because the initial direction isn't given.
 

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