- #1
greyradio
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[SOLVED] Work problem
A vertical rope is used to lower a mass 44.9 kg at a constant acceleration of magnitude 4.57 m/s2. Find the work done by the tension in the cord if the mass moves down distance 2.66 m.
W = F (change in X)
First, I tried to get the tension by:
-T + mg = ma
- T = ma - mg
T = -ma + mg
T = - (4.57 m/s^2)(44.9 kg) + (44.9 kg) (9.81 m/s^2)
T = 235.276 N
W = T (change of x)
W = 235.276 N (2.66 m) = 625.83416
However this seems to be wrong so my second attempt
T -mg = ma
T = ma + mg
T = 645.662 N
W = T (change of x)
W = 645.662 N (2.66 m) = 1717.46092
It seems I'm doing something wrong or overlooking a vital piece of information, I was wondering if someone could point me in the right direction.
A vertical rope is used to lower a mass 44.9 kg at a constant acceleration of magnitude 4.57 m/s2. Find the work done by the tension in the cord if the mass moves down distance 2.66 m.
W = F (change in X)
First, I tried to get the tension by:
-T + mg = ma
- T = ma - mg
T = -ma + mg
T = - (4.57 m/s^2)(44.9 kg) + (44.9 kg) (9.81 m/s^2)
T = 235.276 N
W = T (change of x)
W = 235.276 N (2.66 m) = 625.83416
However this seems to be wrong so my second attempt
T -mg = ma
T = ma + mg
T = 645.662 N
W = T (change of x)
W = 645.662 N (2.66 m) = 1717.46092
It seems I'm doing something wrong or overlooking a vital piece of information, I was wondering if someone could point me in the right direction.