(adsbygoogle = window.adsbygoogle || []).push({}); [SOLVED] Work problem

A vertical rope is used to lower a mass 44.9 kg at a constant acceleration of magnitude 4.57 m/s2. Find the work done by the tension in the cord if the mass moves down distance 2.66 m.

W = F (change in X)

First, I tried to get the tension by:

-T + mg = ma

- T = ma - mg

T = -ma + mg

T = - (4.57 m/s^2)(44.9 kg) + (44.9 kg) (9.81 m/s^2)

T = 235.276 N

W = T (change of x)

W = 235.276 N (2.66 m) = 625.83416

However this seems to be wrong so my second attempt

T -mg = ma

T = ma + mg

T = 645.662 N

W = T (change of x)

W = 645.662 N (2.66 m) = 1717.46092

It seems I'm doing something wrong or overlooking a vital piece of information, I was wondering if someone could point me in the right direction.

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# Work problem

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