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Work Procedure

  • Thread starter xswtxoj
  • Start date
1. The problem statement, all variables and given/known data

A parallel plate capacitor is changed to an electric potential of 334V by moving 3.78e16 electrons from one plate to the other. How much work is charging the capacitor?

2. Relevant equations
Delta V= Delta PE/ q
c=q/v


3. The attempt at a solution
Delta V= Delta PE/ q
rearrange to q * PE = 3.78E16 *334= 1.26E19
 

LowlyPion

Homework Helper
3,079
4
What fraction of a coulomb is the 3.78*1016 electrons of charge?
 

Delphi51

Homework Helper
3,407
10
I don't like the look of your "Delta V= Delta PE/ q" in this case. Due to the fact that the V changes as charge is added to the capacitor, you get a slightly more complicated formula for the energy of the charged capacitor: E = 0.5*Q*V. Roughly speaking, you use the average V so you get a factor of 0.5. Check it out at http://en.wikipedia.org/wiki/Capacitor

Delta V= Delta PE/ q
rearrange to q * PE = 3.78E16 *334= 1.26E19
Here you have rearranged incorrectly. Also, you have entered the charge in non-standard units. The charge is given as a certain number of electron charges, and this number must be multiplied by the charge in Coulombs on one electron.
 
i think i should be the same where 1 j/c is = to 1 Ev, so ur saying the formula can't be done? (E=.5*q*v)
 

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