Would this experiment lights the bulb for a moment?

In summary, according to the conversation, a lightbulb emits radiation in the infrared range, and you need to heat it up to emit visible light. Black-body radiation is the type of radiation emitted by objects like the sun, and it is temperature-dependent.
  • #1
sleepsleep
21
0
hi,
wish to ask, if experiment like below image :
http://img168.imageshack.us/img168/4417/image28ei.png

would the bulb lights for a "moment or X milisecond?" once we touch the wire B to the bulb?

assume the wire B is a long long wire (just wire)
wire A already attached to positive source

thank you in advance.
 
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  • #2
well, the lightbulb is always emitting light in room temperature, but it's in the infrared section of the spectrum, if you want the lightbulb to light in visible light you must make it warm enough.

if you'd put a positively charged object with enough charge on it, it would light the bulb...
 
  • #3
fargoth said:
if you'd put a positively charged object...

you mean positively charged object or negatively charged object?
coz wire A already connected to positive source. :?
 
  • #4
fargoth said:
the lightbulb is always emitting light in room temperature...
does it means the "electrons" on the lightbulb, although not connected with wire ~ just the bulb alone) . are always "moving" (maybe in low potential difference), so the lightbulb would somehow emits the "infrared section of spectrum" ?
 
  • #5
it doesn't matter if the object is charged with a positive charge or a negative one - it's the voltage difference that matters here, not the direction... the current which moves through the lightbulb's wire is only used to heat it up, you don't see light from the current electrons.

the radiation a lightbulb is emitting is of the king of "black body radiation"
according to thermodynamics there's a boltzman destribution of energy states amon every "particle" of the system, when a "particle" is above it's ground state, it will eventually emmit a photon and get to a lower state.
this distribution is dependant upon temperature - you got more excited particles when the temperature is higher.
in room temperature most of the emitted radiation is infra-red, when you warm it up, to say, 2200 kelvin (about 2500 celsius) you get the usual yellowish light you get from a lightbulb. (and if it's 1000 kelvin it'll be red)
in a metal wire the "particles" that emmit the visible raidation are electrons, and that's why is put "" on that word - an electron is hardly a particle in the classical sense.

that's something a little off-topic, but it's a blacl-body radiation example:
most computer screens comes with two pre-set color schemes, one is 9300K (for brighter white - that's what most people prefer to work with)
and 5500K (sometimes 6500K) for image management - because our sun is emmiting light like a blackbody radiation with around 5500K-6000K temperature (the surface temperature of the sun).

when people talk about hues of white, they usually use the Kelvin scale.
 
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  • #6
thank you for your reply, if possible, could you please clarify the following term. (in plain words) ~ coz i am just a physics beginner.

you mentioned about positive charged object and negative charged object, could you please explain them a little bit.

is voltage difference same as potential difference or electric difference?

you mentioned about "particles", if possible, could you give me a rough idea what it is?

sincerely,
thanks a lot and i learn something new "black body radiation" :)
 
  • #7
you're welcom :biggrin:

a positvely carged object is an object who's total charge is positive (i.e. more protons then electrons for normal life objects)
and a negatively charged object is an object who's total charge is negative (i.e. more electrons then protons)..

yes, voltage is electric potential difference - and charge will experience force and thus move (when free) when a a potential difference is introduced, when the voltage increases the force the charge feels increases too.

when i said "particles" i ment every material microscopic object in general, they all obey the same basic statistics - which say that there's a probability for every object to be in an excited state, and the probability for higher energy states increases as the temperature increases.

in the case of the bulb, you got electrons and protons as your "particles"
but the electrons in that wire behave more like waves then anything else.

to learn more about black-body radiation in laymen's terms try looking at howstuffworks.com or wikipedia.org
http://science.howstuffworks.com/light-bulb1.htm
is a good start
 
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  • #8
Good work, Fargoth. I just want to backtrack to the original question for a sec. Sleepx2, your diagram does not indicate a closed circuit. Remember that your negative connection has to be to the 'other side' of the positive source. If you hook one wire to the positive terminal of a battery, and the other to the negative terminal of a different battery, nothing will happen. While Fargoth is correct about the bulb radiating IR, it has nothing to do with your electric circuit.
Pardon the intrusion, but I felt that some clarification was in order. :smile:
 
  • #9
Thanks, Danger.
But in his scheme he drew a charged object, and a long wire, for a split second this long wire can be regarder as ground (and after that split second it will charge-up so that there would be no electric field inside the wire), so there would be a pulse of current through the bulb's wire (it's intensity-time shape depends on the charge amount on the charged object, the resistivity of the long wire, and the length of the wire), until the wire would have a new charge distribution.
div(j) would be non-zero, because charge builds up in the wire, and not just flow through it...

so, yes, the bulb can emmit a flash of visible light if the charged body has enough charge.
i just talked about black body radiation to make it clear that the only part of this pulse of current is heating the bulb's wire up.
(although in this case, because it's a varying current there could be some photons from the current too, but i don't think they're noticable.)
 
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  • #10
Ahhh... gotcha. That's all quite a bit over my head, but it references back to the first thing that I learned about blowing things up. You always lay out your detonator cable before you attach it to the primer cap, because moving it can cause a pulse.
 

FAQ: Would this experiment lights the bulb for a moment?

1. How do you know if an experiment will light a bulb for a moment?

There are a few factors to consider when determining if an experiment will light a bulb for a moment. First, you need to make sure that the experiment involves electricity or a power source that can generate enough energy to light the bulb. Additionally, you need to have a complete circuit, with all the necessary components connected properly. Finally, the materials used in the experiment should be conductive, so that electricity can flow through them and light the bulb.

2. What type of bulb should be used in this experiment to ensure it will light up for a moment?

The type of bulb used in an experiment will depend on the power source and the amount of energy needed to light it up. For example, if the experiment involves a small battery, a small LED bulb would be suitable. If the experiment involves a larger power source, such as a generator, a larger and more powerful bulb may be needed to ensure it lights up for a moment.

3. Is it important to have a specific amount of voltage or current for the bulb to light up for a moment?

Yes, the amount of voltage and current is crucial for the bulb to light up for a moment. The specific amount will depend on the type of bulb used and the power source. Too little voltage or current may not be enough to light the bulb, while too much may cause it to burn out. It is important to carefully measure and control the voltage and current in an experiment to ensure the bulb lights up for a moment.

4. Can any type of material be used to complete the circuit and light the bulb for a moment?

No, not all materials can be used to complete a circuit and light a bulb for a moment. The materials used should be conductive, meaning they can allow electricity to flow through them. Some common conductive materials include copper, aluminum, and graphite. Insulating materials, such as plastic or rubber, cannot be used to complete a circuit and will not light the bulb.

5. How can I make sure the bulb stays lit for a moment in the experiment?

To ensure the bulb stays lit for a moment in an experiment, there are a few things to consider. First, make sure all connections in the circuit are secure and not loose, as this can cause the bulb to flicker or turn off. Additionally, monitor the voltage and current to make sure they are consistent and not fluctuating. Finally, if using a battery, make sure it is fully charged before conducting the experiment.

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