Write a Lisp program to calculate the sum of the first N positive integers

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The discussion revolves around writing a Lisp program to calculate the sum of the first N positive integers. The key insight shared is that the sum can be expressed recursively: the sum of the first N numbers is N plus the sum of the first N-1 numbers. An initial attempt at coding this in Lisp is presented, but it encounters a read error due to syntax issues. The correct approach emphasizes defining a function that checks if N is a positive integer, returning 0 for values less than 1, and recursively calculating the sum for valid inputs. The emphasis is on translating the recursive definition into proper Lisp syntax to avoid errors and achieve the desired functionality.
fernanroy
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Help! Please

I am trying to write a Lisp program to calculate the sum of the first N positive integers where, for example, when N = 6 the sum of the first N = 21

Any Ideas?
 
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Sure: the sum of the first N numbers is N plus the sum of the first N-1 numbers. That's a very strong hint. Heck, it's pretty much exactly the answer in LISP... :-p
 
out of whack said:
Sure: the sum of the first N numbers is N plus the sum of the first N-1 numbers. That's a very strong hint. Heck, it's pretty much exactly the answer in LISP... :-p

Would it be something like this?

(defun nsum (n)
(if (integerp n)
(if (or (= n 0) (< n 1))
Please enter the positive integer
(* n(/ 2(+ n 1))))))

Regards
 
This attempt yields the error: *** Read error: The input could not be tokenized at 2, 2. ***

> (defun sum (n1 n2)
“Returns the sum of two positive integers.”
(assert
(and (integerp n1) (>= n1 0))
(n1)
“N1 must be a nonnegative integer, instead it’s ~S.”
(n1)
(assert
(integerp n2)
(n2)
:N2 must be an integer, instead it’s ~S.”
n2)
(if (zerop n1) n2
(sum (1- n1) (1+n2))))
 
Even more obvious hint: nsum of n is defined as 0 if n is less than 1, otherwise it is n plus the nsum of (n-1). This is true in English, right? So write exactly that, but in LISP instead of English.
 
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