Y to Δ transformation of a circuit

AI Thread Summary
The discussion focuses on using the Y to Δ transformation to solve for current values i0 and ix in a circuit. The calculated value of i0 is confirmed to be 3A, but there is confusion regarding how to isolate and calculate ix. Participants emphasize the importance of recognizing that three resistors can converge at a node, which is crucial for applying the transformation correctly. Clarification is provided about the specific resistors involved in the transformation, particularly the connection of the 4Ω resistor related to ix. The conversation highlights the need for careful analysis of circuit connections regardless of their visual representation.
sevag00
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Homework Statement



Use Y to Δ transformation to find i0 and i/x
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Homework Equations





The Attempt at a Solution



Here's my transformation.
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Calculated i0, which is equal to 3A.
I have no clue how to find ix.
 
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You'll need to find another "Y" to transform that leaves the Ix branch alone... Look for another point where three resistors come together at a node.
 
I can't find any. The others are all deltas.
 
sevag00 said:
I can't find any. The others are all deltas.

That's not true! Three resistors come together at the bottom node, too. Remember, the particular orientation of parts and wires on a circuit drawing is not important. What is important is what is connected to what. The Y in "Y" configuration may look more like an ω if you bend the wires around a bit...
 
Sorry, still no clue.
 
sevag00 said:
Sorry, still no clue.

Bottom central connection is the center of the Y. Three resistors leave that connection point. They are the 'arms' of the Y.
 
Do you mean the 12 ohm resistor that i0 passes through, the bottom 4 ohm resistor and the 4 ohm resistor that ix passes?
 
sevag00 said:
Do you mean the 12 ohm resistor that i0 passes through, the bottom 4 ohm resistor and the 4 ohm resistor that ix passes?

Yes, yes, no. Does the 4 Ω resistor that Ix passes through connect to the bottom node with the others?
 
Hmm. Then it should be the other 4 ohm resistor.
 
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