Y=y(x) of a particle on the xy plane experience F=-kr

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SUMMARY

The discussion focuses on deriving the equation y = y(x) for a particle of mass m moving in the xy-plane under the influence of a force F = -kr directed towards the origin. The motion is described using the position vector r(t) = A_{1}cos(wt) i + A_{2}cos(wt) j, where 'i' and 'j' are unit vectors in the x and y directions, respectively. The solution involves isolating x from the r(t) formula and substituting it back to obtain y, which requires solving two second-order differential equations and determining initial value constants.

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Homework Statement


Assume a particle of mass m which is free to move on the plane x-y. The particle is
experiencing a force F = −kr towards the origin. Find the equation y = y(x) that
describes the motion of this particle on the plane.


Homework Equations



F = ma = -kr

r(t) = A_{1}cos(wt) i + A_{2}cos(wt) j
The 'i' and 'j' above should be unit vectors in the x and y direction, respectively.

The Attempt at a Solution



I think I'm supposed to use the r(t) formula above to isolate x, then substitute it back into the equation to get y?
 
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You have two second-order differential equations, one for the motion in the x plane, and another for the motion in the y plane. you are missing two initial value constants.
 
Thank you for the reply. I figured it out shortly after.
 

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