Yo-Yo Homework: Find Average Force on String

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The discussion revolves around calculating the average force on a Yo-Yo string as it unwinds and reverses direction. Key equations include the relationship between linear and angular velocity, and the conservation of energy principle. The user has successfully derived the final angular velocity but struggles to determine the average force, questioning how uniform spin affects angular momentum. Clarification is sought on the concept of "average force" in this context. The conversation highlights the complexities of rotational dynamics and the need for a clear understanding of force definitions in motion.
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Homework Statement



A Yo-Yo of mass M has an axle of radius b and a spool of radius R. Its moment of inertia can be taken to be MR^{2}/2 and the thickness of the string can be neglected. The Yo-Yo is released from rest. The center of the Yo-Yo descends distance h before the string is fully unwound. Assuming it reverses direction with uniform spin velocity, find the average force on the string when the Yo Yo turns around.

Homework Equations



v=bα v = linear velocity of the yoyo. α= angular velocity of the yoyo.

\frac{1}{2}Mv^{2} + \frac{1}{2}Iω^{2} = Mgh

The Attempt at a Solution



From the constraint equation and the energy conservation I calculated final ω. Now change in angular momentum is 2Iω. Now I can't find the average force from here.
 
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You are asked to assume a uniform spin velocity - since the rotation changes neither rate not direction (constant velocity) how does it change angular momentum?

What changes direction when the yo-yo reaches the bottom of the string?

You do have a problem with "average force" though ... what would this mean?
 
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