# Young's Modulus homework

## Homework Statement

I had to do an experiment and create a graph with the data.
We attached one end of the Iron wire to a clamp and then tied on weights of 100g at a time to the other end so that a force can be applied to the Iron wire and so it stretches. (as pizza1512 did but in copper)

## Homework Equations

Diameter of wire: 0.31mm (therefore area is 0.302mm²)
Length of wire: 2m70cm (270cm)

## The Attempt at a Solution

i worked out that if u apply 100g (1newton force)
1/2700= 3.7x10^-4 (not sure if right)

And stress is
1/0.302= 3.3

I worked out the Youngs Modulus
3.3/(3.7x10^-4) and i got 8918.92

is that right?
and how do i plot it on a graph

LowlyPion
Homework Helper

## Homework Statement

I had to do an experiment and create a graph with the data.
We attached one end of the Iron wire to a clamp and then tied on weights of 100g at a time to the other end so that a force can be applied to the Iron wire and so it stretches. (as pizza1512 did but in copper)

## Homework Equations

Diameter of wire: 0.31mm (therefore area is 0.302mm²)
Length of wire: 2m70cm (270cm)

## The Attempt at a Solution

i worked out that if u apply 100g (1newton force)
1/2700= 3.7x10^-4 (not sure if right)

And stress is
1/0.302= 3.3

I worked out the Youngs Modulus
3.3/(3.7x10^-4) and i got 8918.92

is that right?
and how do i plot it on a graph

How did you work that out? From what? What are the units of that expression?

It is for Strain.
it extended by 1mm
so,
1mm/2700mm (length of wire) =3.7^-4

LowlyPion
Homework Helper
It is for Strain.
it extended by 1mm
so,
1mm/2700mm (length of wire) =3.7^-4

$$E = \frac{\sigma}{\epsilon} = \frac{F*L}{A_o*\Delta L} = \frac{1N * 2.7m}{.302*10^{-6}m^2*.001m}$$