CoolDude420
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gneill said:For ##Z_{11}## I think my approach would be to assume ##V_1## as a source, then find the ##i_1## that results. Either nodal or mesh analysis looks promising. If you're familiar with the use of supermeshes, then one loop equation will suffice (along with whatever auxiliary equations are required to satisfy the current source constraint).
You want only one source there, so either leave the current source as is, or replace it with a voltage source. If you leave the current source, then that would fix the mesh current for its loop, or can be used as a branch current for nodal analysis. Then you'd need to find a way to determine the voltage across it. If you replace it with a voltage source, then you will solve for the mesh (or branch) current instead, giving you both the voltage and current needed for the Z-parameter.CoolDude420 said:So I should put a V1 voltage source in parralel with the current source on the left?
gneill said:You want only one source there, so either leave the current source as is, or replace it with a voltage source. If you leave the current source, then that would fix the mesh current for its loop, or can be used as a branch current for nodal analysis. Then you'd need to find a way to determine the voltage across it. If you replace it with a voltage source, then you will solve for the mesh (or branch) current instead, giving you both the voltage and current needed for the Z-parameter.
If you're going to use nodal analysis, you'll want to define your reference node and solve for the voltage at node A, since that's where you're summing currents. Note that ##V_2## can be written in terms of ##V_A##, since ##V_2## appears along a single branch leading from node A.
In this case you don't have to transform the source as you might convert a Norton current source to a Thevenin voltage source. Simply swap the current source for a voltage source. There are two variables of interest here: the voltage and current produced by whichever source is in that place. Their ratio will determine the impedance you're seeking. You can specify either the current or the voltage, then determine the resulting value of the other quantity.CoolDude420 said:Oh. I see. Just another thing, how would I change that current source into a voltage source. The way we usually did it was if there was a resistor in parallel with that current source but in this case there's no resistor.
gneill said:In this case you don't have to transform the source as you might convert a Norton current source to a Thevenin voltage source. Simply swap the current source for a voltage source. There are two variables of interest here: the voltage and current produced by whichever source is in that place. Their ratio will determine the impedance you're seeking. You can specify either the current or the voltage, then determine the resulting value of the other quantity.