Zero Induced EMF in a Changing Magnetic Flux Loop

AI Thread Summary
A circular wire loop with a radius of 19 cm is placed in a uniform magnetic field of 0.670 T, which is decreasing at a rate of -1.2×10−2 T/s. To achieve zero induced electromotive force (emf) in the loop, the area must increase at a specific rate to counterbalance the changing magnetic field. The relevant equation for this scenario is -(dɸ)/(dt) = emf, where the magnetic flux (ɸ) depends on both the magnetic field and the area of the loop. The discussion highlights the need to differentiate the flux with respect to time, considering both the changing magnetic field and area, while noting that the angle remains constant. The solution involves using geometric relationships to find the required rate of area increase.
Melqarthos
Messages
11
Reaction score
0

Homework Statement



A circular wire loop of radius r= 19 cm is immersed in a uniform magnetic field B= 0.670 T with its plane normal to the direction of the field.


If the field magnitude then decreases at a constant rate of −1.2×10−2 , at what rate should increase so that the induced emf within the loop is zero?

Homework Equations



Basically the most relevant equation is:

-(dɸ)/(dt)=Emf

The Attempt at a Solution



I'm not too sure how to attempt this problem. It would be greatly appreciated if someone could get me started.

-Melqarthos
 
Physics news on Phys.org
Melqarthos said:
If the field magnitude then decreases at a constant rate of −1.2×10−2 , at what rate should increase so that the induced emf within the loop is zero?

At what rate should what increase? The radius? or just the area of the wire?

In order for the induced EMF to be zero, -(dɸ)/(dt) = 0. ɸ = B*Area if the field is perpendicular to the loop. You have dB/dt by the problem statement, so you should be able to solve for dA/dt and dr/dt using geometric relations. Also note that when you differentiate the flux, that both the area and the magnetic field are time-dependent.
 
What do you mean by geometric relations? I'm not quite sure.
 
Never mind. I got it. we just use this relationship:

(dΦ)/(dt)=(BcosΘ)(dA/dt)+(AcosΘ)(dB/dt) + AB(-sinΘ)(dΘ/dt), in which case the last term is equal to zero as the angle does not change. Only the magnitude and area change.

Thanks!

Melqarthos
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top