I understood where was my mistake. I assume average velocity as final velocity which is wrong (Big mistake)
I did a resume (attaching here)with my new procedure and possible graph just to leave a possible guide for anyone with similar question
I have a new question based in what I found
I add...
the v equal to 0.7407 should final velocity, d is displacement and t is the time over which the displacement occurs. The initial velocity should be 0 .
So, the question is, when can I say the area under the graphs (v x t) represents the displacement?
I assume the acceleration is constant...
The graph is not a measure but could you please explain me why the distance in the second graph is only obtained by multiply the area of the rectangle and not the triangle?
v=d/t = 0.92m/ 1.242 sec = 0.7407 m/s and it is totally correct at least there is a new rule in the physics
The...
Hello
This is not a homework, this is my own experiment to understand how the motion works. Please, follow my question here below:
I have a hot wheels race with a slope with 10 degrees where I use a small car which departs from the top to the bottom. I have taken 5 times the time to get an...
I appreciate you took your time for answering but to be honest, it is not enought. I would like to know why the mass is not affceting this force
Regards,
Hello guys,
The third law says:
"For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second...
Thanks for your response. The blue line is just the total displacement but this is parabolic trajectory, for sure, there are a X and Y component.
So, what it would be the equation for the parabolic trajectory ?
With this equation I think I can implement a derive, isn't it?
So, you mentioned it...
Hello everyone,
I have a problem where I have to find the final displacement and final velocity which I have found however, I want to post few variations for that same problem which I am curious. It is more for my own knowledge > I would appreciate any help
Please follow graph below with...