Actually, part 3 of this paper does well to explain it. However, in this paper they do not have the percentage of relevant items on hand.
http://ciir.cs.umass.edu/pubfiles/ir-224.pdf
It is generally found that the output scores of a reasonable information retrieval system will have a distribution that can be approximated by a mixture model consisting of one exponential distribution and one Gaussian distribution. The exponential distribution representing the scores for...
I have a list of scores between 0 and 1 generated by an information retrieval system - 1 being very relevant and 0 being completely non-relevant. I do not know whether the scores correspond to relevant or non-relevant items or not but I do know that the distribution of scores is generated by a...
I think Simon's point was helpful to confirm and clear up some of my confusion regarding density functions and how to interpret the value of a density function. The other part that I needed to clear up was to go back and review the generalization of Bayes' Theorem to continuous distributions and...
I thought I understood all the theory quite well and sat down to begin coding until I realized that calculating a probability at a point within a normal distribution in the application of bayes' rule you can't simply plug the point into the normal distribution and get the value since the...
I think this contains what I'm looking for but have not dug in yet since this problem has been set aside temporarily.
http://dare.uva.nl/document/125861
The general issue I'm having here surrounds ranked retrieval. I have rankings and they do work and I can present them in descending order to...
I have a set of scored items with the scores in the interval [0,1]. Roughly speaking the distribution of scores is about 50% equal to 0 and then sloping steeply downward all the way toward one or near to one. I want to fit this data to a distribution and use that down the road in some...
As I understand it, one result of the central limit theorem is that the sampling distribution of means drawn from any population will be approximately normal. Assume the population consist of Bernoulli trials with a given probability p and we want to estimate p. Then our population consist of...
I'm going through the Degroot book on probability and statistics for the Nth time and I always have trouble 'getting it'. I guess I would feel much better if I understood how the various distribution arose to begin with rather than being presented with them in all there dryness without context...
I've come across using partial derivative notation for taking the partial derivative of a function f with respect to a vector x. I've never seen this before. It is also being referred to as a gradient. However, I have only seen gradients where all variables in the space are featured in the...
You're right. I must have had brain leakage. I believe I'm a bit off on orthogonality too. I believe they are orthogonal only when the norm of R(t) is constant on an interval.
In general, I'm not seeing how the statement A dot B = norm(A) * norm(B) can be true since a vector valued function...
From the calculus of vector valued functions a vector valued function and its derivative are orthogonal. In euclidean n-space this would mean cos Θ = 1 and hence the dot product of A and B would be the norm of A times the norm of B.
So my understanding of your question is you want to know...
I do admit that I have been confused by the fuzzy use of differential notation and I still am quite often. But I'm fairly certain that dx is an approximation of Δx. The increment is the actual change in a value whereas dx is an approximation of that change using the derivative. It is certainly...
Consider the indefinite integral, which is just antidifferentiation. For the indefinite integral of f(x) we want to find the function y = F(x) such that F'(x) = f(x). In differential notation that is dy/dx = f(x) or else dy = f(x) dx. So antidifferentiation is just finding the differential of...
I agree, it is not a children's show. Perhaps some don't regard it as serious science fiction because it has other elements besides science fiction. I don't think all science fiction has to be like Star Trek. I take it seriously - thank you.
On the other hand the Matt Smith Doctor Who can...