How Much Energy is Needed to Transform Ice into Water and Steam?

  • Thread starter Thread starter physics1234
  • Start date Start date
  • Tags Tags
    Ice Steam Water
AI Thread Summary
To calculate the energy needed to transform a 55 g ice cube at 0°C into water and steam, the process involves three stages: melting the ice, heating the water, and vaporizing the steam. The correct approach requires using the latent heat of fusion for the melting phase, the specific heat capacity for heating the water, and the latent heat of vaporization for converting water to steam. The calculations should account for the full 55 g of ice melting and then heating the resulting water from 0°C to 100°C before vaporizing 15 g of that water. The initial calculations provided were incorrect due to not fully considering all phases of the transformation. Accurate energy calculations are essential for understanding phase changes in thermodynamics.
physics1234
Messages
21
Reaction score
0
A 55 g ice cube at 0°C is heated until 40 g has become water at 100°C and 15 g has become steam at 100°C. How much energy was added to accomplish the transformation?

I tried using Q=mL for each change and adding them together.

Q=.055(3.33x10^5)
Q=18315

then

Q=.015(2.26x10^6)
Q=33900

18315+33900= 52215 which is not the correct answer.
 
Physics news on Phys.org
You have 55g melting (latent heat of fusion) and 55g warming from 0° C to 100° C and then 15g vaporizing (latent heat of vaporization).
 

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
View full post »

Similar threads

Calorimetry: Finding mass of ice, water, steam left
Replies
1
Views
4K
How much ice to cool down this water?
Replies
17
Views
5K
Heat Transfer. Ice and steam in a container (easy)
Replies
2
Views
4K
Thermodynamics: Steam is added to an ice cube
Replies
16
Views
3K
Calculate the Mass of Ice cubes needed to cool a soft drink
Replies
10
Views
3K
Thermodynamics (final temperature, ice mixed with steam)
Replies
3
Views
9K
How Much Steam Is Needed to Heat Water from 24°C to 90°C?
Replies
1
Views
3K
Mixing water with steam, find equilibrim
Replies
14
Views
3K
Equilibrium temperature of some ice and steam
Replies
9
Views
4K
Solving Heat Transfer Problem with Melting Ice Cube
Replies
4
Views
4K

Hot Threads

Recent Insights

Back
Top