How Do You Calculate the Charge and Number of Excess Electrons on a Pith Ball?

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To calculate the charge on a pith ball that hangs at a 20-degree angle and is influenced by a charged rod, one must consider the forces acting on the ball. The weight of the ball and the electrostatic force from the charged rod create a system that can be analyzed using Newton's second law. A free-body diagram is essential to set up the equations, resulting in two equations with two unknowns: the charge (q) and the tension (T) in the cord. The distance moved by the ball (10 cm) and the angle from the vertical are crucial for determining the components of the forces involved. Solving these equations will yield the charge in coulombs and the number of excess electrons on the ball.
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Homework Statement


My problem states that a pith ball hangs at 20 degrees from the verticle and weighs 3 grams. It is moved 10cm by a charged rod. They both have the same charge. It asks what is the charge on the ball in C and approximatley how many excess electrons are on the ball.


Homework Equations


I have the equation kqq/rsquared


The Attempt at a Solution


I found all the sides to the triangle and I do not know where to go from there. I do not know the charges so how can I use the equation with q in it?
 
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ehdubbya said:
It is moved 10cm by a charged rod.

10 cm in which direction? x? y? other? And where is the rod in relation to the ball? Is the charge distributed over the entire rod, or is it concentrated at a point?



I found all the sides to the triangle and I do not know where to go from there. I do not know the charges so how can I use the equation with q in it?

Did you draw a free-body diagram and set up the equations from Newton's second law? You should have 2 equations in 2 unknowns (q and the tension T in the cord from which the ball hangs).
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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