How is the Intensity of Electric Field Related to the Permittivity Constant?

[n0_3sc]

Can anyone explain how to go from:

I_s = \frac{nc\epsilon}{2} |E|^2
to
I_s = \frac{nc}{8\pi} |E|^2

That means \epsilon is \frac{1}{4\pi}...I can't find that anywhere.

 

[dynamicsolo]

Can anyone explain how to go from:

I_s = \frac{nc\epsilon}{2} |E|^2
to
I_s = \frac{nc}{8\pi} |E|^2

That means \epsilon is \frac{1}{4\pi}...I can't find that anywhere.

Is your source using something like statcoulombs as units? I think the units are defined so that \epsilon_{0} is set to 1...

 

[n0_3sc]

It says its using "cgs" units.
By the way \epsilon I quoted, is the same as \epsilon_0.

 

[pam]

Your first equation is in SI units. The epsilon there is epsilonzero.
The second equation is in cgs gaussian units.
To go from SI to gaussian, let 4piepsilonzero-->1.

 

[n0_3sc]

Ahh ok - thanks a lot pam.