What Does the 'Kissing Circle' Reveal About Momentum and Net Force?

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The discussion focuses on calculating the rate of change of momentum and the net force for an object moving in a circular path. The object has a constant speed of 31 m/s and a radius of curvature of 4 m, with a momentum of 87 kg·m/s. Participants express confusion about how to apply the relevant equations, particularly regarding units and the relationship between velocity, radius, and time. The rate of change of momentum is linked to centripetal acceleration, and the net force can be derived from the change in momentum over time. Clarification on these calculations is sought to resolve the confusion.
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The "kissing circle"

Homework Statement


An object moving at a constant speed of 31 m/s is making a turn with a radius of curvature of 4 m (this is the radius of the "kissing circle"). The object's momentum has a magnitude of 87 kg·m/s.
What is the magnitude of the rate of change of the momentum?
What is the magnitude of the net force?


Homework Equations


p = mv
\Deltap = Fnet\Deltat
dp/dt = magnitude of V / R (sry don't know how to put that in latex)

The Attempt at a Solution


Question 1: Velocity divided by radius? Using the 3rd equation, but the units don't check out.
I am lost
Question 2: How do I find t, and afterwards, the answer would be Fnet = 87 (change in momentum) * t (change in time)
 
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the rate of change of momentum is just acceleration so you need to find the centripetal acceleration.
 

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