Who I can find the displacement in this Q ?

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To find the total displacement of a jetliner landing at 90 m/s, it first travels for 2 seconds at constant speed, resulting in a displacement of 180 meters. After applying brakes that decelerate at 20 m/s², the second displacement can be calculated using the equation v² = v0² + 2aDx, leading to a value of 202.5 meters. The total displacement on the runway is then the sum of both displacements, which equals 382.5 meters. The discussion highlights the importance of correctly applying kinematic equations to solve for displacement in motion problems. Understanding these calculations is crucial for accurately determining distances in physics scenarios.
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Hi all



who I can find the displacement in this Q ?



A jetliner lands with a speed of 90 m/s on runway . It runs with constant speed for 2 s , before the brakes are applied . The brakes produce a deceleration of 20 m/s2 . What is its displacement on the runway .



I try to solve



V0 = 90 m/s

t1 = 2s

x = V0 X t1 = 180 m

a = -20 m/s2



then I don't know who I complte it ?
 
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Hi r-soy! :smile:

(btw, it's how (rhyming with now and Mao) not who (rhyming with new and you) :wink:)
r-soy said:
A jetliner lands with a speed of 90 m/s on runway . It runs with constant speed for 2 s , before the brakes are applied . The brakes produce a deceleration of 20 m/s2 . What is its displacement on the runway .

This is how

The total displacement is the sum of the two displacements.

Your first displacement is ok.

For the second displacement, use one of the standard constant acceleration equations, with distance = s, acceleration = a = -20, u = 90, and v = 0. :wink:
 
see

Here I must find two displacement .
firist one I got it
now the secound now

I have Dx1 = 180 and a = -20, u = 90, and

by equat5ion constant I use v^2 = v0^2 = 2aDx
fainal velocity is 0 beacuse it will stop after using brake
now :
0 = 90^2 + 2(-20) Dx2
Dx2 = 202.5

Now collect two dispkacement : will get : 362.5 m
 
(try using the X2 tag just above the Reply box :wink:)

Yes, that's fine :smile:

(except 180 + 202.5 = 382.5 :wink:)
 
Hmm not sure what you guys are talking about..but il get it later.
 
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