Temperature and pressure gradient in a gas

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A temperature gradient in a gas within a tube does not create a pressure gradient, as the pressure remains constant throughout the system. The temperature will vary linearly from one end of the tube to the other, but this does not affect the overall pressure. Molar density at any point in the tube is determined by the constant pressure and the varying temperature, following the ideal gas law. The total number of moles in the tube can be calculated using the integral of the temperature function along the length of the tube. This analysis contradicts the initial claim that a temperature difference leads to a pressure gradient.
rejeev
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I have derived that, when there is a temperature difference (gradient) in a gas (consider a long tube with one end maintained at 100oC and other end maintained at 0oC), there will be a pressure gradient (something similar to Bernoulli's law).
Please see the attached document or this link for details: http://rejeev.blogspot.com/2010/07/pressure-and-temperature-gradient-in.html"
I would like to know the feedback from the community on this.
 

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rejeev said:
I have derived that, when there is a temperature difference (gradient) in a gas (consider a long tube with one end maintained at 100oC and other end maintained at 0oC), there will be a pressure gradient (something similar to Bernoulli's law).
Please see the attached document or this link for details: http://rejeev.blogspot.com/2010/07/pressure-and-temperature-gradient-in.html"
I would like to know the feedback from the community on this.
The analysis is incorrect. There will be a linear temperature gradient from A to B but the pressure will be constant. If the pressure is constant, the molar density at point x along the tube will be ##\frac{P}{RT(x)}##. So the total number of moles in the tube will be $$n=\int_0^L{\frac{P}{RT(x)}Adx}=\frac{PV}{R}\frac{1}{L}\int_0^L{\frac{dx}{T(x)}}$$ where A is the cross sectional area of the tube and V is the tube volume.
 
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