What Minimum Diameter Must a Brass Wire Have to Withstand 350 N of Tension?

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To determine the minimum diameter of a brass wire that can withstand a tensile force of 350 N, the ultimate tensile strength of brass is essential. The discussion highlights the relationship between stress, force, and cross-sectional area, emphasizing that Young's modulus alone is insufficient without knowing the tensile strength. Participants suggest that tensile strength should be used instead of Young's modulus for this calculation. The lack of specific tensile strength data or a graph is noted as a limitation in solving the problem. Ultimately, the conversation centers on the need for tensile strength to accurately calculate the wire's required diameter.
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1. The Problem...

A brass wire is to withstand a tensile force of 350 N without breaking. What minimum diameter must the wire have?

Given Quantity: Young's modulus for brass = 9.0 * 10^10

2. What I Thought I Needed to Solve It...

Young's modulus = Tensile strength/Tensile strain

Stress = Force/cross section area

Strain = distance stretched/initial length

3. I only know 2 of the 5 variables; how much force will be applied and Young's modulus. I'm not sure where to go without knowing the stretch or length of the wire.
 
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Is it even solvable? Or is there something painfully obvious that I'm missing?
 
Young's modulus is a measure of stiffness: how difficult it is to achieve elastic, reversible deformation. You need to look up the strength of brass: the ultimate tensile strength that it can withstand without breaking.
 
GrandLuxor said:
1. The Problem...

A brass wire is to withstand a tensile force of 350 N without breaking. What minimum diameter must the wire have?

Given Quantity: Young's modulus for brass = 9.0 * 10^10

2. What I Thought I Needed to Solve It...

Young's modulus = Tensile strength/Tensile strain

Stress = Force/cross section area

Strain = distance stretched/initial length

3. I only know 2 of the 5 variables; how much force will be applied and Young's modulus. I'm not sure where to go without knowing the stretch or length of the wire.
You only need to know the ultimate breaking tensile stress of brass using the original area; were you given a graph?
EDIT: oohh, way too late with this response.
 
I wasn't provided a graph, or a figure for the tensile strength of Brass. If I was to use tensile strength rather than Young's modulus, would the same equation apply?
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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