How Do I Calculate the Net Force on Sphere A in This Coulomb's Law Problem?

AI Thread Summary
To calculate the net force on sphere A, first determine the forces exerted by spheres B and C. Sphere B, with a negative charge, will attract sphere A, resulting in a force directed along the positive x-axis. Conversely, sphere C, with a positive charge, will repel sphere A, creating a force directed along the negative x-axis. The net force on sphere A can be found by subtracting the force from sphere C (which is negative) from the force from sphere B (which is positive). This approach ensures that the effects of both charges are accurately accounted for in the final calculation.
mimictt
Messages
8
Reaction score
0
I don't really know how to solve this problem. I only know how to calculate the net force on B, not A...

here is the problem:
sphere A is located at the origin and has a charge of +2.0x10^-6 C.
Sphere B is located at +.6m on the x-axis and has a charge of -3.6x10^-6 C. Sphere C is located at +.8 m on the x-axis and has a charge of +4.0x10^-6 C. Determine the net force on sphere A.


I know how to find the net force on sphere B, since it's in the middle... but i have no idea when it comes to sphere A... would the net force on sphere A be the same as the net force on sphere C?

Thank you!

PS:im new to this forum! :D
 
Physics news on Phys.org
Write forces on A, the one acting along +X axis ... take them positive and the opposite, take them negative ...

Keep in mind that like charges repel and unlike charges attract!
 
cupid.callin said:
Write forces on A, the one acting along +X axis ... take them positive and the opposite, take them negative ...

Keep in mind that like charges repel and unlike charges attract!

meaning that i should calculate the FC on A and FB on A
and then subtract these two forces to get a net force on A?
 
yes
because C will push A along -X and B will attract A along +X
 
cupid.callin said:
yes
because C will push A along -X and B will attract A along +X

THank you so much! :smile:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top