How to find magnitude of centripetal acceleration and of net force?

AI Thread Summary
The magnitude of the centripetal acceleration for riders on a ferris wheel with a radius of 12 m and speed of 8 m/s is calculated to be 5.33 m/s². To find the net force required for a rider with a mass of 70 kg, the centripetal acceleration is multiplied by the mass. The net force is therefore 5.33 m/s² multiplied by 70 kg, resulting in a total force. The calculations confirm the correct application of the formulas for centripetal acceleration and net force. Overall, the discussion emphasizes the straightforward nature of these physics problems when the formulas are applied correctly.
starplaya
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Homework Statement


A ferris wheel at a carnival has a radius of 12 m and turns so that the speed of the riders is 8m/s
a) what is the magnitude of the centripetal acceleration of the riders?
b) what is the magnitude of the net force required to produce this centripetal acceleration for a rider with a mass of 70kg?


Homework Equations



Centripetal acceleration = v^2/r
F = ma
Fnet = N - W = m(centripetal acceleration)

The Attempt at a Solution



centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
 
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starplaya said:
centripetal acceleration = 8^2/ 12 = 5.33 m/s^2
Looks good.
 
Doc Al said:
Looks good.

so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
 
starplaya said:
so, 5.33 m/s^2 would be the answer for part A and for part B i just multiply the acceleration by the mass?
That's correct.
 
Boy was I over thinking that. Thanks a lot for the clarification
 

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