What Is the Capacitance of a Parallel-Plate Capacitor with Circular Plates?

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The discussion focuses on calculating the capacitance of a parallel-plate capacitor with circular plates measuring 8.80 cm in radius and 1.50 mm apart. The relevant formula used is C = (k * ε₀ * A) / d, where k is approximately 1 for air, ε₀ is the permittivity of free space, A is the area of the plates, and d is the separation distance. Participants clarify the values needed for the calculation, emphasizing the importance of showing work to verify answers. The discussion highlights confusion around the variables R and L, which are not applicable in this context. Ultimately, the correct approach to finding capacitance in picofarads (pF) is confirmed.
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[SOLVED] Capacitors VERY QUICK EASY QUESTION! PLEASE HELP!

Homework Statement



A parallel-plate capacitor has circular plates of 8.80 cm radius and 1.50 mm separation.
(a) Calculate the capacitance.
 
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THE answer has to be in pF for part a)
 
I don't know what R is, and I don't know what L is. I can assume that A is the area, but the equation your teacher gave you makes no sense to me, as the equation for a parallel plate capacitor is:

C=\frac{k\epsilon _0A}{d}

For air or free space, k is about 1.

There's also another equation:

C=\frac{Q}{V}
 
Distance of separation.
Area.
Capacitance
Voltage
\epsilon_0=8.85\times10^-12 \frac{C^2}{Nm^2}
Q = charge
 
1808
 
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I can't say if the answer is right or wrong without you showing any work.
 
Looks right.
 
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