Solve for Equation of Motion in Tricky Mechanics Homework

  • Thread starter Thread starter JohnSimpson
  • Start date Start date
  • Tags Tags
    Mechanics
AI Thread Summary
The discussion focuses on deriving the equation of motion for a mechanics problem involving a massive bar connected to a spring and mass. The main challenge is calculating the kinetic energy of the bar, specifically determining the angular velocity (omega) for the second term of the kinetic energy equation. The user struggles with how the center of mass movement affects the rotation of the bar and seeks suggestions for finding omega or alternative approaches. A hint is provided that omega can be expressed as the derivative of the angle with respect to time (dθ/dt). Overall, the conversation emphasizes the complexities of rotational dynamics in this context.
JohnSimpson
Messages
89
Reaction score
0

Homework Statement



See attached figure. Derive the equation of motion for the following in the parameter \theta

Homework Equations





The Attempt at a Solution



The only part that's giving me trouble is the uppermost massive bar connecting the spring to the mass. I am trying to write down its kinetic energy. I know this can be decomposed as

<br /> T = \frac{1}{2}m\bar{v}^2 + \frac{1}{2}I_{CM}\omega^2<br />

where v-bar is the center of mass velocity and omega is the angular velocity of the body about its CM. I can get the first term, but I can't begin to figure out how to get Omega in the second term. I thought about considering a small change in the position of the mass, as this of course gives rise to a rotation of this bar, but the CM moves during this and it throws me off. Suggestions on how to get Omega, or on an alternative approach would be appreciated.
 

Attachments

  • ques.JPG
    ques.JPG
    8.1 KB · Views: 387
Physics news on Phys.org
Hmmm, after another attempt I still can't make heads or tails of finding Omega
 
Hi John! :smile:
JohnSimpson said:
Hmmm, after another attempt I still can't make heads or tails of finding Omega

?? :confused: ω = dθ/dt :wink:
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top