Statics: Bending of a beam/evenly distributed force problem

AI Thread Summary
The discussion centers on a statics problem involving bending stress in specific incisions. The user seeks clarification on the calculation of bending moment (Mb) at incision 2, particularly the term involving the evenly distributed force (q). There is confusion about the factor of 1.25 used in the equation, as the user expected it to be divided by 2 instead. Additionally, there are questions about the symbols used, specifically aA and Mb, and the reactions at points A and B. The conversation suggests starting with equations for bending moments to better understand the problem.
hattori_hanzo
Messages
8
Reaction score
0
Hello, and sorry for my English, as I am Norwegian.

I have a statics problem which I can not understand.

I've taken a pic from my book:
eFcrt.jpg


The problem asks me to find the largest bending stress, σb, in the incisions 1 and 2.

I have the solution in front of me, I just don't understand what they have done with the evenly distributed force (q). Especially in incision 2, when they find Mb, they have used: Mb = FA*aA-q*2.5m*1.25.

The q*2.5m I can understand, but where does the 1.25 come from? I thought it should be divided by 2?

Can someone explain how this works for me?
 
Physics news on Phys.org
Especially in incision 2, when they find Mb, they have used: Mb = FA*aA-q*2.5m*1.25.

Please confirm what the symbols stand for.

In particular what is aA and Mb ?

You have not provided symbols for the reactions at A and B?
Do you know how to calculate these reactions?

You should start by writing the equation for the bending moments for 16.2 and 16.3, using x for the horizontal axis and starting with x=0 at A. Can you do this?
It will have the form M = some function of x and the loads to the left of x.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Maxwell’s equations imply the following wave equation for the electric field $$\nabla^2\mathbf{E}-\frac{1}{c^2}\frac{\partial^2\mathbf{E}}{\partial t^2} = \frac{1}{\varepsilon_0}\nabla\rho+\mu_0\frac{\partial\mathbf J}{\partial t}.\tag{1}$$ I wonder if eqn.##(1)## can be split into the following transverse part $$\nabla^2\mathbf{E}_T-\frac{1}{c^2}\frac{\partial^2\mathbf{E}_T}{\partial t^2} = \mu_0\frac{\partial\mathbf{J}_T}{\partial t}\tag{2}$$ and longitudinal part...

Similar threads

Replies
59
Views
4K
Replies
19
Views
1K
Replies
2
Views
2K
Replies
9
Views
2K
Back
Top