How is Vmax Derived as 2πfA from Given Formulae?

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The maximum speed (Vmax) of a mass on a spring can be derived as 2πfA by manipulating the given equations. Starting with the formula Vmax = 2πfA, squaring it leads to Vmax² = (2πf)²A². Substituting the expressions for frequency and the relationship between force and mass allows for simplification. The amplitude is at its maximum when the velocity is also at its peak, confirming the derivation. This process clarifies how Vmax is linked to frequency and amplitude in harmonic motion.
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Given the following formulaes prove that maximum speed (Vmax) of a mass on a spring is given by 2(pi)(frequency)(Amplitude)

(constant k) A^2 = mv^2 + (constant k) x^2 ma = -(constant k)(x)

f = 1/2(pi) sqrt (a/-x) and f = 1/2(pi) sqrt (constant k/m)

i just don't see how i can make it work... any suggestions?
 
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quickslant said:
Given the following formulaes prove that maximum speed (Vmax) of a mass on a spring is given by 2(pi)(frequency)(Amplitude)

(constant k) A^2 = mv^2 + (constant k) x^2

ma = -(constant k)(x)

f = 1/2(pi) sqrt (a/-x)

f = 1/2(pi) sqrt (constant k/m)

i just don't see how i can make it work... any suggestions?

You need to use carriage returns to put equations on separate lines. Extra spaces do not get included in posts.

Start with 2(pi)(frequency)(Amplitude) and square it. Then make substitions.
 
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What happens to the amplitude when the velocity is at its maximum?
 
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