Horizontal Circular Motion FBD Diagram Help

AI Thread Summary
In the discussion about drawing a free body diagram (FBD) for a rubber stopper in horizontal circular motion, participants clarify the forces acting on the stopper. The primary forces identified include the gravitational force acting downward and the tension force directed towards the center of rotation. It is noted that the tension force is not purely horizontal but at a slight angle, affecting its components. The centripetal force is explained as the horizontal component of the tension force, which is crucial for maintaining circular motion. Understanding these forces is essential for accurately representing the dynamics of the stopper in the FBD.
BayernBlues
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Homework Statement


Draw and FBD of a rubber stopper (mass) in circular horizontal motion. Be realistic here: Is the tension force on the stopper truly horizontal?

This question is from an experiment where a rubber stopper is tied to a string and swung horizontally. When the question says "Be realistic here," it means that the rubber stopper is being swung horizontally but at a slight angle (such as 10 degrees) below the horizontal.


Homework Equations





The Attempt at a Solution



I know that there's going to be a Fg downwards on the stopper, and a Force of tension going from the stopper to the centre of rotation, but I'm not sure about other forces such as Fc and which direction it would be going.
 
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BayernBlues said:

Homework Statement


Draw and FBD of a rubber stopper (mass) in circular horizontal motion. Be realistic here: Is the tension force on the stopper truly horizontal?

This question is from an experiment where a rubber stopper is tied to a string and swung horizontally. When the question says "Be realistic here," it means that the rubber stopper is being swung horizontally but at a slight angle (such as 10 degrees) below the horizontal.


Homework Equations





The Attempt at a Solution



I know that there's going to be a Fg downwards on the stopper, and a Force of tension going from the stopper to the centre of rotation, but I'm not sure about other forces such as Fc and which direction it would be going.
You've got them all. When drawing a FBD, generally you look for two types of forces: gravity and contact. Here, you have correctly identified the gravity force (the objects weight) and the contact force (the tension in the cord).
The centripetal force is not an additional force; it is the horizontal component of the tension force that provides the inward centripetal acceleration necessary to keep the object moving in a horizonatal circle.
 
So Ftx and Fc are equivelant. That's good, I'm done that part then.
 
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