Graphing a Function with No Local Minimum at x=2 and Differentiable at x=2

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sketch the graph of a function that has no local minimum at 2 and is differentiable at 2

this is confusing, how come this is an upside down parabola, it makes sense, but how do i know what kind of graph to draw
 
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There must be more to the question. Infinitely many functions have no local minima at 2 and are differentiable there. What else is given in the problem or in the discussion that precedes the problem?
 
mmm, no what i wrote it wrong i meant local maximum, my bad.
 
Well, maybe when they said sketch the graph of *a* function, they meant any of the infinitely many functions that obey the criteria. Woudn't a horizontal line work?
 
Again, are you sure you have written the problem correctly? Almost any graph except the upside down parabola you mention would work. Are you sure the problem did not say "has a local maximum at x=2" rather than "has no local maximum"?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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