How Do You Calculate Total Image Distance in a Dual Lens System?

  • Thread starter Thread starter Diiyad
  • Start date Start date
  • Tags Tags
    Multiple
AI Thread Summary
To calculate the total image distance in a dual lens system, start by determining the image formed by the converging lens using the lens formula 1/f = 1/o + 1/i. The object distance for the converging lens is 30 cm, and its focal length is 10 cm, leading to the formation of an image that serves as the object for the diverging lens. The diverging lens, with a focal length of -15 cm, will then create its own image based on the new object distance. The final step involves calculating the total distance from the original object to the final image formed by the diverging lens. A diagram is recommended for better visualization of the lens arrangement and distances.
Diiyad
Messages
1
Reaction score
0

Homework Statement

;

A Converging Lens, with focal length of 10 cm, is 60 cm to the left of a Diverging Lens, with focal length 15 cm. The Object distance is 30 cm to the left of the Diverging Lens. What is the total distance between the starting object and the final image?


Homework Equations

;
1/f = 1/o + 1/i


The Attempt at a Solution

;
I tried to solve this problem, but I can't understand how to do it because it is a multiple lens problem, however, the object is in the middle of the two lenses. Any help?

(Need a Diagram as well)
 
Physics news on Phys.org
Diiyad said:
1. ... The Object distance is 30 cm to the left of the Diverging Lens. ...


The real object is to the left of the converging lens. It forms an image at the given distance of 30 cm from the diverging lens. This image is now the object for the diverging lens. The problem requires you to calculate the distance between the real object to the left of the converging lens and the final image formed by the diverging lens.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

Similar threads

Back
Top