Electromagnetic radiation wavelength

AI Thread Summary
The discussion focuses on calculating the wavelength of electromagnetic radiation with a frequency of 5.00x10^14 Hz. The wavelength in a vacuum is determined to be 600 nm, indicating it is in the orange range of the visible spectrum. In water, the wavelength is calculated to be approximately 451 nm due to the index of refraction of 1.33. The index of refraction for a medium where the speed of light is 2.54x10^8 m/s is discussed, emphasizing the relationship between speed, wavelength, and frequency. The conversation also touches on everyday encounters with this type of radiation, such as traffic lights.
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An Electromagnetic radiation has a frequency of 5.00x10^14 hx.
a) Calc its wavelength in a vacuum in metres and nanometres
b)Calc its wavelength in water
c)is this radiation visible? if so wat colour?
d) What is the index of refraction of a medium in which the speed of this radiation is 2.54x10^8m/s?
e)where would u encounter this radiation in your daily life?

My attempt...

a)c=f(wavelength) wavelength = 3x10^8/5x10^8
=600nm and 6.00x10^-7 m

b)n=1.33 in water ?=6.00x10^-7/1.33
wavelength =600nm =451nm
wavelength in median ??

c)yes this radiation is visible and according to the visible spectrum, 590-610nm is orange so its at 600nm so it is orange.

d)i cannot do this question, can anyone help me??

e)same with this one
 
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d)c=f(wavelength)
2.54x10^8/5x10^14=wavelenngth
=5.08x10^-7m or 508 nm but that is now totally different from my other wavelength in a) this question is confusing...please help
 
The index of refraction of a medium is the ratio of the speed of light in vacuum (air) to its speed in the medium.

The frequency stays the same in both media, it is the wavelength that changes. Your ratio is the wrong way round.

Traffic light?
 
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