Rate of Current: Solve Homework Equation for US Students

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A canoist rows upstream for 2 miles before turning around and returning to the starting point simultaneously with a log floating downstream. The problem involves determining the rate of the current, denoted as c, while assuming the canoist's speed, v, is constant. The equations derived from the distances and effective speeds for both upstream and downstream travel can be used to create a system of equations to solve for the unknowns v and c. The discussion highlights the challenge of the problem, which was presented as a joke by the teacher, emphasizing its difficulty for U.S. students. The key to solving the problem lies in setting up the correct equations based on the canoist's travel times and distances.
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Homework Statement


A canoist is rowing upstream a river. After 2miles he passes a log (traveling with the current) he continues to row for one more hour and turns around. He reaches his starting point at the same time as the log. What is the rate of the current?


Homework Equations





The Attempt at a Solution


v1+v2/c
To be honest I don't even know where to begin with this problem. The teacher gave it to us as a joke because he said this was something from his high school book in Russia and hasn't found anyone in the U.S who can solve it.
 
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Draw a picture.

the start point = 0---------------- log position= 2miles ------------- turnaround point

So suppose the current's speed is c.

What is the position of the turnaround point in terms of c?

Where is the log located when the rower reaches the turnaround point?
 
Assume that the speed v of the canoist (with respect to current) is constant, or the average speed is constant for the different phases of the trip. The current's speed is constant c.

Traveling upstream, the distance traveled is (v-c)*t, and down stream the effective speed is v+c. Knowing the times and distances, one should be able to find two equations to solve to the two unknowns, v and c.
 
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