How Much Total Kinetic Energy Do Split Nucleus Fragments Have?

AI Thread Summary
The discussion revolves around calculating the total kinetic energy of two equal fragments resulting from the spontaneous split of a nucleus with a mass of 222.0 u. The fragments each have a mass of 110 u, and the problem specifies that the initial energy is equal to the final energy. Participants are considering the correct setup of the energy equation, which includes the kinetic energy of both fragments and their rest mass energy. There is a suggestion to use more precise values for the mass of u and the conversion factor for energy. The conversation emphasizes the need for accuracy in calculations to determine the correct total kinetic energy.
quickclick330
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Homework Statement



6. A nucleus of mass Mo=222.0 u at rest spontaneously splits into two equal fragments,
each of mass M=110 u. When these two fragments are far apart, how much total kinetic
energy do they have? That is, what is the sum of their individual kinetic energies? (Note
that 1 u= 1.7 x 10^-27 kg, and 1 uc2 = 15.3 x 10^-11 J.)


1. 3.060 x 10-10 J
2. 3.366 x 10-10 J
3. 3.672 x 10-10 J
4. 3.978 x 10-10 J
5. 4.284 x 10-10 J
6. 4.569 x 10-10 J


No surroundings so...

Ef = Ei


would the equation be...

KE(of both) + Mc^2 + Mc^2 = Moc^2


is this set up right? thanks!
 
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Right.
 
quickclick330 said:

Homework Statement



6. A nucleus of mass Mo=222.0 u at rest spontaneously splits into two equal fragments,
each of mass M=110 u. When these two fragments are far apart, how much total kinetic
energy do they have? That is, what is the sum of their individual kinetic energies? (Note
that 1 u= 1.7 x 10^-27 kg, and 1 uc2 = 15.3 x 10^-11 J.)


1. 3.060 x 10-10 J
2. 3.366 x 10-10 J
3. 3.672 x 10-10 J
4. 3.978 x 10-10 J
5. 4.284 x 10-10 J
6. 4.569 x 10-10 J
Judging by the available answers, I think you have to specify u to more significant figures. u = 1.67x10^-27 kg. (mass of proton), 1 uc2 = 15.03 x 10^-11 J.

AM
 
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