Weight of Object: Calculating Force from Acceleration

  • Thread starter Thread starter subieman
  • Start date Start date
  • Tags Tags
    Weight
AI Thread Summary
To calculate the weight of an object given its acceleration and net force, the relevant formula is F = m * a, where F is force, m is mass, and a is acceleration. Given a net force of 2.0 N and an acceleration of 1.0 m/s², the mass can be calculated as m = F/a, resulting in a mass of 2.0 kg. The weight of the object can then be determined using the formula weight = m * g, where g is the acceleration due to gravity (approximately 9.81 m/s²). Therefore, the weight of the object would be approximately 19.62 N. Providing an initial attempt at a solution is essential for receiving help in such discussions.
subieman
Messages
5
Reaction score
0
If an object has an acceleration of 1.0m/s and net force is 2.0N what is the weight?
 
Last edited:
Physics news on Phys.org
You will not an answer so easily on this website. For one, this should be posted in the homework section of the site, but secondly, and perhaps more importantly, you must provide an attempt at a solution before I (or, hopefully, anyone else) will help you.
 
Do you know any formulas that involve acceleration, force, and weight (or maybe just mass)?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Back
Top