Finding electric potential difference to stop a electron between 2 plates

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SUMMARY

The discussion centers on calculating the electric potential difference required to stop an electron traveling at a velocity of 5.0 x 10^6 m/s, injected into a parallel plate apparatus. The problem specifies that the electron must be stopped 25% of the way across the gap between the plates. The correct potential difference is determined to be 285 J/C (or 285 V) based on the conservation of energy equations, specifically using the formula Vq + 1/2 mv^2 = Vq(0.75). The user initially miscalculated but was confirmed to be on the right track.

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mjolnir80
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Homework Statement



Question: an electron with a velocity of 5.0x10^{}6 m/s is injected into a parallel plate apparatus through a hole in the positive plate. it moves across the vacuum between the plates. what would the potential difference have to be in order to stop the electron 25% of the way across the gap?

Homework Equations


conservation of energy eqations and electromagnetic equations

The Attempt at a Solution


if we set the base line at the positive plate:
E_{}kinetic 1 + E_{}electric potential 1 = E _{}electric potential 2

Vq + 1/2 mV^{}2 = Vq(0.75) <---- (to account for the 25%)

V(-1.6 x 10^{}-19 ) + 1/2 (9.1 x 10^{}-31 )(5x10^{}6) ^{}2 = V(-1.6x10^{}-19)(.75)

when i do this my answer does not come out to what it is supposed to (which is 285 j/c)
what am i doing wrong
 
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I get 285V when I work through your numbers. Your doing the problem correctly, but you may have made an error in computing the numbers. Check your calculations for an error.
 
kewl thanks for confirming that
 

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