Total angular momentum quantum number

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To calculate the total angular momentum quantum number J for the electron configuration 1s^2 2s^2 2p^2 3p^1, the contributions from each shell must be considered. In the n=1 and n=2 states, both the s shells contribute zero angular momentum (L=0) and total spin (S=0). In the n=2 p shell, two electrons contribute L=2, but their spins cancel out to give S=0. The n=3 p shell contributes L=1 and S=1/2 from the single electron. Therefore, the total angular momentum J is calculated as J=L+S=2+1+1/2=7/2, which is correct.
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lets say there is an electron configuraiton of 1s^2 2s^2 2p^2 3p^1

I want to find the total angular momentum quantum number, J=L+S

considering the n=1 state, there are two electrons, in the s shell which means one is spin 1/2 and the other is spin -1/2 giving a total spin of 0. The s shell has no angular momentum so L=0.

considering n=2 state, there are two electrons in the s shell which again gives us 0 total angular momentum. If we went to the p shell, there are 2 electrons in the p shell, each having L=1, so we add them together to get L=2. The two electrons do not contribute spin since their net sum is zero, S=1/2-1/2=0.

considering the n=3 state, there is 1 electron in the p shell, which means S=1/2 and L=1

J is the sum of L and S, so the total angular momentum should be J=L+S=2+1+1/2=7/2

Is this correct?
 
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