Magnetic field of an infinite layer

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The discussion focuses on proving that the magnetic field above an infinite layer with thickness D and current density J is constant regardless of height z. Participants suggest using Ampère's law for the proof, emphasizing the need to choose an appropriate rectangular path for integration. The symmetry of the problem indicates that the magnetic field component in the z-direction can be considered, leading to a conclusion about the integral of B over the rectangle's sides. The key point is to ensure that the integration results in a value independent of z, confirming the constancy of the magnetic field above the layer. This approach highlights the importance of symmetry and careful path selection in electromagnetic calculations.
Dell
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given a n infinite layer, with a thickness of D and a current density of J direction in the diagram (on x-), prove that the magnetic field above the layer is constant irrespective of the height 'z'

http://lh4.ggpht.com/_H4Iz7SmBrbk/Si1JMFGiWEI/AAAAAAAABEE/LVo64TBgsmw/Untitled.jpg

i had a similar problem in electrostatics and what i did was use gauss law, here what i want to do is use amperes law, the problew is finding the correct path to use. i think that it must be a rectangle path therefore my closed integration will be in 4 parts, 2 along the y axis, 2 along the z axis,, i thought of taking a path of length L, at a height Z,

somehow i need to get 0 for the integration of the heights, so that my equation is independant of z
 
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Dell said:
given a n infinite layer, with a thickness of D and a current density of J direction in the diagram (on x-), prove that the magnetic field above the layer is constant irrespective of the height 'z'

http://lh4.ggpht.com/_H4Iz7SmBrbk/Si1JMFGiWEI/AAAAAAAABEE/LVo64TBgsmw/Untitled.jpg

i had a similar problem in electrostatics and what i did was use gauss law, here what i want to do is use amperes law, the problew is finding the correct path to use. i think that it must be a rectangle path therefore my closed integration will be in 4 parts, 2 along the y axis, 2 along the z axis,, i thought of taking a path of length L, at a height Z,

somehow i need to get 0 for the integration of the heights, so that my equation is independant of z
Take any rectangular path enclosing the full thickness of a section of the slab that is in the yz plane.

By symmetry, what can you say about the component of B in the z direction? What does this say about \int B\cdot ds over the two sides of the rectangle in the z direction?

AM
 
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